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Take a blank graph with 'x' and 'y' axes on it.
Draw a 45-degree line on the graph. The line goes through the origin, and from the
origin, it goes down-left and up-right. The slope of the line is 1, and its equation is y=x.
The region "y is greater than or equal to x" is every point on that line, plus every point
on the side above it (to the left of it).
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ReneTo graph x ≥ y, you would first plot the line y = x. Since x is greater than or equal to y, the region above the line y = x (including the line itself) is shaded. This shaded region represents all the points where x is greater than or equal to y. The line y = x acts as the boundary between the two regions.
If you start with the x and y axes being perpendicular to each other and with the same scale, then the graph of x = y is the straight line at a 45 degree angle to the axes, going from bottom left to top right. For any point to the right of this graph, x is greater than y.
So the answer is the area which comprises the x=y line along with any point to the right of the line.
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Find the graph of the inequality y plus 2 -x - 6?
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What is C Cx plus 2y x plus y greater or equal to 8 x greater or equal to 3 y greater or equal to 0?
what is c, x + 2y, x+y equal to or greater than 8, x equal to or greater than 3, y equal to or greater than 0.
In which quadrant will the area be if x is greater than or equal to 0 and y is less than or equal to 0?
Picture a coordinate axes with the x-axis on the horizontal and the y-axis on the vertical in typical fashion. X is greater than or equal to 0 in the 1st and 3rd quadrants. Y is less than or equal to zero anywhere under (or equal to) the x-axis. The 3rd quadrant is where both conditions occur together.
Graph the system of inequalities for y greater than equal to - 3 and x greater than equal to 6?
Break the question down into two separate equations: Y >= -3 and x >= 6. The graph for the first equation looks like a horizontal line going through point (0,-3) with all of the space above the equation shaded in. The line is a solid line in the solution of equation #1. For equation #2 (x>=6) the graph would look like a solid vertical line that goes through point (6,0). Everything to the right of the line would be shaded in. The system of inequalities would be everything that includes both of these shaded areas or the area in which these two inequalities intercept. So everything shaded that is in both of these inequality equations colors would be the answer - including any point that may be on either line.
What are graphs that cannot represent functions?
Consider the graph of y= +/- sqrt(x). Notice that, for any value of x greater than 0, there are two values of this relation. To be a function a relation has to assign one value in the range to each value in the domain. So this cannot be a function, yet it has a perfectly ordinary graph.
