y = 10 + (-6x)
y = 10 - 6x
First, compare this graph to its simplest form. This linear function has the slope-intercept form
y = mx + b. Where m = slope and b is the y-intercept. In this case
y = -6x + 10
so the slope is -6 and the y-intercept is 10. Therefore, we know that one point on the graph is (0,10). For a line, we need two points before we can draw it on a graph. An easy to find second point is the x-intercept. This occurs when y = 0. Solve for x:
0 = -6x + 10
-10 = -6x
10/6 = x
5/3 = x.
So a second point on a graph of this line is (5/3,0). Now draw both of these points on the graph and, using a ruler, make a straight line between and beyond them.
Zero out the variables in turn for two points ( which is all you really need ), or start plugging in values into X,
Y = 6X + 10
zero out Y
6X + 10 = 0
6X = - 10
X = - 5/3
---------------
zero out X
Y = 6(0) + 10
Y = 10
------------------connect these two points
or put values into X
X = 1
6(1) + 10 = 16, which is the value of Y
so, this way you can plot many more points to get your line
x=5. 10x-4x (6x) +10-6x (=10) If 10 is 2x, x=5.
5x + 32 = 11x - 105x - 11x = -10 - 32-6x = -42x = 7
4x+6x=30 is the same as: 10x=30 so we divide by 10 and get: x=3 (I do not see how this relates to calculus, but O.K.)
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
3x - 12 = 10x - 15 - 6x -10 3x - 12 = 4x -25 3x + 13 = 4x 13 = 4x - 3x 13 = x None?
x=10
The picture of the graph is in the related links section.
The lines are parallel.
negative one and a half
6x + 10 + 4x = 5010x + 10 = 5010x = 40x = 4
If 6x + 10 = 11x , then x=2.
Two straight lines that intersect.
10+12x=-14 -14-10=12x 12x=-24 x=-2
10
10
3x + 6x +1 = 10 9x = 10 - 1 9x = 9 x = 1
8x+2=6x+10 8x-6x=10-2 2x=8 x=4 Therefore, x=4.