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More answers

y = 10 + (-6x)

y = 10 - 6x

First, compare this graph to its simplest form. This linear function has the slope-intercept form

y = mx + b. Where m = slope and b is the y-intercept. In this case

y = -6x + 10

so the slope is -6 and the y-intercept is 10. Therefore, we know that one point on the graph is (0,10). For a line, we need two points before we can draw it on a graph. An easy to find second point is the x-intercept. This occurs when y = 0. Solve for x:

0 = -6x + 10

-10 = -6x

10/6 = x

5/3 = x.

So a second point on a graph of this line is (5/3,0). Now draw both of these points on the graph and, using a ruler, make a straight line between and beyond them.

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Wiki User

13y ago
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Zero out the variables in turn for two points ( which is all you really need ), or start plugging in values into X,

Y = 6X + 10

zero out Y

6X + 10 = 0

6X = - 10

X = - 5/3

---------------

zero out X

Y = 6(0) + 10

Y = 10

------------------connect these two points

or put values into X

X = 1

6(1) + 10 = 16, which is the value of Y

so, this way you can plot many more points to get your line

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Wiki User

13y ago
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Q: How do you graph y equals 10 plus -6x?
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