negative one and a half
20x+12y = 2012 12y = -20x+2012 y = -5/3x+503/3 Therefore the perpendicular slope is the positive reciprocal -5/3 which is 3/5
12y + 5 = 53 12y = 48 y = 4
12y+2=146 12y=146-2 12y=144 144/12 12x12=144 y=12
12y - 4 = 7y + 165y = 20y = 4
6y + 4.. i think
20x+12y = 2012 12y = -20x+2012 y = -5/3x+503/3 Therefore the perpendicular slope is the positive reciprocal -5/3 which is 3/5
6x - 12y = 24 Algebraically rearrange -12y = -6x + 24 Multiply both sides by '-1' Hence 12y = 6x - 24 Factor out '6' on both sides. 2y = x -4 Divide both sides by '2' y = (1/2)x - 2 Hence the gradient is ' 1/2' and the y-intersect is ' - 2' .
12y + 5 = 53 12y = 48 y = 4
17/12
-6x + 12y = -102 -6x = -12y - 102 x = 2y + 17
12y+2=146 12y=146-2 12y=144 144/12 12x12=144 y=12
12y - 4 = 7y + 165y = 20y = 4
7X - 12Y = 96 - 12Y = - 7X + 96 Y = (7/12)X - 8 ============== m = 7/12 Y intercept = - 8
-8x + 12y = 24 Algebraically rearrange 12y = 8x + 24 Reduce by a factor of '4' 3y = 2x + 6 Divide both sides by '3' y = (2/3)x + 2 Hence it is a straight line of slope/gradient ' 2/3' and a y-intersect of '2'.
12y+3=9y-15 3y=-18 y=-6
6y + 4.. i think
its 10x +9y +1z