-3
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If you mean x-4 = x-1 then there is no solution for x as the x's would cancel each other out if you tried to move them across.
By x3 I assume that you mean x3. In which case f(x)=x3-2x+1, and f'(x)=3x2-2. Therefore our iteration formula is: xn+1=xn- (xn3-2xn+1)/(3xn2-2) Starting with x0=0 we get: x1=0.5 x2=0.6 x3=0.617391304 x4=0.618033095 x5=0.618033988 x6=0.618033988 Starting with x0=0.9 we get: x1=1.065116279 x2=1.009457333 x3=1.000255451 x4=1.000000195 x5=1 x6=1 Starting with x0=-1.5 we get: x1=-1.631578947 x2=-1.618183589 x3=-1.618034007 x4=-1.618033989 x5=-1.618033989 The 3 real roots to f(x) are x=-1.618033989, x=0.618033988, and x=1
inverse matrix. x1+x2+x3=3,000 -x1+5x2=0 2x1-3x3=0.
it equals x1 it equals x1
X^4 ? 4x^3
point slope form is y-y1=m(x-x1). x1 and y1 are both points and m is the slope.