Q: How do you solve 3x 15?

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Do you mean 3x = 45 then if so divided both sides by 3 to find the value of x which is 15

Add 5 to both sides of the equation to get rid of the - 5. -3x - 5 + 5 = -20 + 5 Solve and simplify. -3x = -15 Divide both sides of the equation by -3. x = 5

8-3x = 128 -3x = 128-8 -3x = 120 x = -40

3x = (96-75) 3x = 21So X = 7

If 15 + 3x = 42, then x = 9

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4x+7-3x = 15 4x-3x = 15-7 x = 8

-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5

-3x + 5 = 20 -3x = 15 x = -5

3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5

x + 5 = 4x/3 Solve for x multiply both sides of the equation by 3... 3 * (x + 5) = 3 * (4x/3) 3x + 15 = 4x subtract 3x from both sides of the equation (3x + 15) - 3x = (4x) - 3x 15 = x x = 15

3x + 5 = 20 Subtract '5' from both sides 3x = 15 Divide both sides by '3' x = 5 The answer!!!!!

Since there are no brackets or parentheses, the divisions must be evaluated from left to write so that the expression is ((25/5x)/15)/3x = ((5/x)/15)/3x = (5/15x)/3x = (1/3x)/3x = 1/(9x2)

8-3x=238-8-3x=23-8 subtract 8 from both sides-3x=15-3x/-3 = 15/-3 divide both sides by -3 to solve for xx = -5

3x = 15 >> 3x = multiplication, and the opposite of multiplication is division. So you take 3x, draw a line under it to show division, then write 3. After that, cross out the 3x/3. With algebra what you do to one side, you do to the other, so then you take 3 and divide it by 15. >>the answer>> X=5

3x+5 = 4x-10 In algebra, what you do to one side you do the other Now you add 10 to both sides 3x+5 + 10 = 4x-10+10 3x +15 = 4x now subtract 3x from both sides 3x-3x +15 = 4x-3x 15 = x

To solve the equation -3 + 3x + 6x = 15, combine like terms: 9x - 3 = 15. Then, add 3 to both sides: 9x = 18. Finally, divide both sides by 9 to solve for x: x = 2.

Do you mean 3x = 45 then if so divided both sides by 3 to find the value of x which is 15