3X = X + 58
subtract X from both sides
2X = 58
divide both sides by 2
X = 29
check
3(29) = 29 + 58
87 = 87
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The conclusion is easy. Take your numbers 68 and 126, and subtract. 126 - 68 equals 58, so 58 is the value of x.
Assuming the formula that was meant was x^2 plus 8x minus 5 equals 0 [ x^2 + 8x - 5 = 0 ] the quadratic formula uses the standard form of a quadratic ax^2 plus bx plus c = 0 [ax^2 + bx + c = 0] comparing this form to the equation we get a = 1 b = 8 and c = -5 the quadratic formula is: x = negative b plus or minus the square root of (b^2 minus 4ac) all over 2a [ x = (-b +- root(b^2 - 4ac))/2a ] if we substitute in the values we have for a, b and c we get x = negative 8 plus or minus the square root of (8^2 minus 4*1*(-5)) all over 2*1 [ x = (-8 +- root(8^2 - 4*1*(-5)))/(2*1) ] simplified we get x = (-8 +- root(64 + 20))/2 and x = (-8 +- root(84))/2 and x = (-8 +- 2*root(21))/2 we get two solutions x = (-8 - 2*root(21))/2 x approx= (-8.58) and x = (-8 + 2*root(21))/2 x approx= (.58)
In this type of problem let the numerator of a fraction be 23.29 and its denominator be twice the coefficient of the variables and so:- 29*(23.29/58)+23*(23.29/46) = 23.29 Therefore the possible values of x and y are 23.29/58 and 23.29/46 respectively
25xy is an equivalent expression.
The correct answer is 10*9/2 = 45. The 45 are: 01, 02, 03, 04, 05, 06, 07, 08, 09 12, 13, 14, 15, 16, 17, 18, 19, 23, 24, 25, 26, 27, 28, 29, 34, 35, 36, 37, 38, 39, 45, 46, 47, 48, 49, 56, 57, 58, 59, 67, 68, 69 78, 79, 89. In a combination, the order of the elements DOES NOT MATTER.