The conclusion is easy. Take your numbers 68 and 126, and subtract. 126 - 68 equals 58, so 58 is the value of x.
Assuming the formula that was meant was x^2 plus 8x minus 5 equals 0 [ x^2 + 8x - 5 = 0 ] the quadratic formula uses the standard form of a quadratic ax^2 plus bx plus c = 0 [ax^2 + bx + c = 0] comparing this form to the equation we get a = 1 b = 8 and c = -5 the quadratic formula is: x = negative b plus or minus the square root of (b^2 minus 4ac) all over 2a [ x = (-b +- root(b^2 - 4ac))/2a ] if we substitute in the values we have for a, b and c we get x = negative 8 plus or minus the square root of (8^2 minus 4*1*(-5)) all over 2*1 [ x = (-8 +- root(8^2 - 4*1*(-5)))/(2*1) ] simplified we get x = (-8 +- root(64 + 20))/2 and x = (-8 +- root(84))/2 and x = (-8 +- 2*root(21))/2 we get two solutions x = (-8 - 2*root(21))/2 x approx= (-8.58) and x = (-8 + 2*root(21))/2 x approx= (.58)
In this type of problem let the numerator of a fraction be 23.29 and its denominator be twice the coefficient of the variables and so:- 29*(23.29/58)+23*(23.29/46) = 23.29 Therefore the possible values of x and y are 23.29/58 and 23.29/46 respectively
25xy is an equivalent expression.
I presume that you mean 5x + 3y + 20 = 0 and 2x - y - 14 = 0. First put the formulae in the form y = mx + c. 3y = -5x -20 y = -5/3 x -20/3 and y = -2x + 14 Substitute the second formula into the first -2x - 14 = -5/3 x -20/3 -6x - 42 = -5x - 20 -42 = x - 20 x = -22 Substitute into equation y = -2x + 14 y = -2 x -22 + 14 y = 44 + 14 y = 58 Therefore the two lines meet at point (-22, 58).
12x + 131 = 189 + 3x 12x - 3x + 131 - 189 = 0 9x - 58 = 0 9x = 58 x = 6,44444
Yes and their solutions are x = 41 and y = -58
a=5: c=4
-8x + 6 = -58 -8x = -64 x= -64/-8 x = 8
58
They are simultaneous equations and their solutions are x = 41 and y = -58
366
To solve for x: 2x2 + 10 = 58 2x2 = 48 x2 = 24 x = √24 x = √4 × √6 x = 2√6
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2
58 + 7 + 7 = 72
58 + 37 = 95
105