What are the possible values of x and y when 29x plus 23y equals 23.29 showing work in detail?

Answer 1

In this type of problem let the numerator of a fraction be 23.29 and its denominator be twice the coefficient of the variables and so:-

29*(23.29/58)+23*(23.29/46) = 23.29

Therefore the possible values of x and y are 23.29/58 and 23.29/46 respectively

Answer 2

The equation represents a straight line and so there are infinitely many possible solutions.

29x + 23y = 23.29

23y = 23.29 - 29x

y = (23.29 - 29x)/23

For each value of x, the above equation needs to be solved for y.

Answer 3

Your problem, 29x + 23y = 23.29, is a binomial linear equation. One principal that isn't necessarily taught in High School algebra is that when dealing with linear equations you will find an infinite number of possible solutions. This is because a straight line can never end on an infinite plane.

At most, you could express the answer to this problem by giving a few points of reference for graphing purposes, but as for solving it, it has no solution because it's solutions are infinite. (In mathematical terms, All rational numbers are solutions to an infinite set).

Let's start by isolating either variable. Let's work with x.

• 29x + 23y = 23.29
• (We will set our "y" to 0, so we can solve for an x coordinate.
• 29x + 23(0) = 23.29
• 29x = 23.29
• 29x/29 = 23.29/29
• x = ~.803

We will now repeat these same steps, except, we'll need to solve for "y".

• 29x + 23y = 23.29
• 29(0) + 23y = 23.29
• 23y = 23.29
• 23y/23 = 23.29/23
  
• y = 1.01

Therefore, we could say that an answer to this graph (.803, 1.012)