0
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x,
therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2
therefore, (Ln + [X/3]) = 1
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∙ 13y ago
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How do you solve this log x base 3 plus log x3 base 9 equal 0?
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-6
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If it is 20(3-3) it is equal to 0. 20X3-3= 57
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0
What does a negative 10 minus a negative 10 equal?
-10 minus -10 is 0.
