When finding an antiderivative, substitution can be very helpful. In your integral expression, look for a term that, if you took the derivative and perhaps manipulated it a bit, would give you another term in the same equation. For example, if your integral is ∫tanxdx or ∫((sinx)/(cosx))dx , you can choose cosx as your arbitrary variable (often u or w). If u=cosx, du=-sinxdx. Therefore, your expression using u becomes -∫du/u. We know that the antiderivative of 1/u is ln (absolute value x) +C. So, our answer with u is -ln (abs. val. u) +C. But BE CAREFUL, this is not your final answer. You must plug in the value you originally designated as u. Therefore, the final answer is -ln (abs. val. cosx) +C, with C as an arbitrary constant.
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- ln (cscx + cotx) + C You use u substitution.
Oh, dude, like, the substitution method is cool because you can easily solve for one variable and plug it into the other equation. But, like, it can get messy with fractions and decimals. The elimination method is great for getting rid of one variable right away, but it can be a pain to keep track of all those plus and minus signs. So, like, pick your poison, man.
maybe it means to use a calculator
When you have a problem that you need to solve!
If done properly there are no disadvantages.