The quadratic formula is "[minus b] over 2a, plus or minus the square root of [b squared minus 4ac], over 2a".
where the formula for the variable is in the form
a(x2) + b(x) + c = 0
By setting the equation into this form, you can use the integer values a, b, and c to find the solution for x, simply by multiplying, taking the square root, and adding. As the equation describes a curve, the two solutions (plus or minus) are the x-intercepts (y=0) of the curve, and the y-intercept (x=0) is at c.
* For the shorter form ax2 + 2kx + c where k is an even number, see the related link.
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2a-3+4b-2a-b-3+5=3b-1
The discriminant, because it helps you to discriminate between the type (and number) of roots.
Use the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2aUse the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2aUse the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2aUse the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2a
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the quadratic formula is [ neg. b plus or minus the square root of (b squared minus 4ac) ] all divided by 2a ur question doesnt have and =, +, or - so it cant be effectively solved