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The quadratic formula is "[minus b] over 2a, plus or minus the square root of [b squared minus 4ac], over 2a".
where the formula for the variable is in the form
a(x2) + b(x) + c = 0
By setting the equation into this form, you can use the integer values a, b, and c to find the solution for x, simply by multiplying, taking the square root, and adding. As the equation describes a curve, the two solutions (plus or minus) are the x-intercepts (y=0) of the curve, and the y-intercept (x=0) is at c.
* For the shorter form ax2 + 2kx + c where k is an even number, see the related link.
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2a -3 plus 4b - 2a -b -3 plus 5?
2a-3+4b-2a-b-3+5=3b-1
What is b squared minus 4ac called in the quadratic formula?
The discriminant, because it helps you to discriminate between the type (and number) of roots.
Find all complex solutions for the equation x2 equals 4x - 29?
Use the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2aUse the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2aUse the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2aUse the quadratic formula. In x2 - 4x + 29 = 0, a is 1, b is -4, c = 29. The quadratic formula is: x = (-b plusminus squareroot(b2 - 4ac)) / 2a
X squared - 4x - 21?
-17
F x x2 x 2 To find the x intercept let f x 0 and solve for x Factor complete the square or use the quadratic formula?
the quadratic formula is [ neg. b plus or minus the square root of (b squared minus 4ac) ] all divided by 2a ur question doesnt have and =, +, or - so it cant be effectively solved
What is the quadraic formula?
-b + or - the square root of b squared - 4ac over/divided by 2a
What are the solutions to the quadratic formula?
The quadratic formula is x=-b (+or-) square root of b2-4ac all over 2a
2A plus 3B times 2A - 3B?
2A plus 3B times 2A - 3B = 4A2 - 9B2; this is an example of the general formula (a + b)(a - b) = a2 - b2.
What is the equation for the axis of symmetry of a parabola?
x=-b/2a [negative B over 2A]
What is 2a-b over a plus 5?
7
How do you transpose A equals half h times a plus b to solve for a formula is for a trapezium?
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
How does the formula -b over 2a give the x value of the vertex given ax2 bx c?
From the quadratic formula, the zeros (where y=0) is -b/(2a) +/- sqrt(b^2 -4ac)/(2a). The expression inside the square root is known as the descriminant. Being that the parabola is symmetric, one of the zeros will be at the vertex + sqrt(b^2 -4ac)/(2a) and the other zero is at vertex - sqrt(b^2 -4ac)/(2a). The vertex is halfway between these two values, so the x coordinate of the vertex is -b/(2a). Or if you use Calculus, you can take the derivative of f(x) = ax^2 + bx + c. f'(x) = 2ax + b. Set equal to zero and solve for x. x = -b/(2a).
What is the axis of symmetry formula?
-b/2a. i think.To show this, consider this equation:y = ax² + bx + cFactor out the a:y = a(x² + bx/a + c/a)Then, complete the squares to get:y = a(x² + bx/a + (b/(2a))² + c/a - (b/(2a))²)= a((x + (b/2a))² + c/a - (b/(2a))²)= a(x + (b/2a))² + c - b/(4a)By the vertex form:y = a(x - h)² + k where x = h is the axis of symmetry.So the general axis of symmetry for the quadratic equation is x = -b/(2a).
A 2b a b 2a b 2a?
a-^2a-b^-a-b
Formula for finding zeros of polynomial function?
Try the quadratic formula. X = -b ± (sqrt(b^2-4ac)/2a)
Where did the quadratic formula come from?
The quadratic formula originated from the concept of completing the square. let's take ax2 + bx + c = 0. To complete the square, solve for x. Subtract c. ax2 + bx = -c. Then divide by a [notice- if there is no a value, then a=1]. x2 + bx/a = -c/a. Add (b/2a)2 to both sides. x2 + bx/a + b2/4a2 = -c/a + b2/4a2 Factor/Reformat. (x + b/2a)2 = (b2-4ac) / 4a2 (x + b/2a)2 = [(b2-4ac) / 2a]2 Square-root both sides. x + b/2a = ± √(b2-4ac) / 2a Subtract b/2a. x = -b/2a ± √(b2-4ac) / 2a Combine terms. x = [-b ± √(b2-4ac)] / 2a
Ax2 plus bx plus c equals 0?
x=(-b+sqrt(b^2-4*a*c))/(2a) and (-b-sqrt(b^2-4*a*c))/(2a) (This is called the quadratic formula)
