You can make 125 different 3-digit numbers if you're allowed to repeat a digit (for example, 113, or 545), and 60 if you're not. If repetitions are allowed, then there are 5 ways to choose each digit to be 1,2,3,4, or 5, so the total number of ways is 5*5*5 or 125. If no repetitions are allowed, there are 5 ways to choose the first digit, but only 4 ways left to choose the second (for a total of 5*4=20 ways to choose the first two digits), because it can't be the same as the first. Then you have eliminated two choices for the third digit, so there are only 3 ways to choose it, for a total of 5*4*3=60 different 3-digit numbers.
2+3+9=14 9+_+8=17+8=25 25-14=11
With each digit having only 2 possibilities, the answer is 2 to the 4th power, which is 16. The 4 is because there are 4 digits. Think about the binary numbers 0000 to 1111, there are 2 possibilities for each digit. If your constraint is that the digits must have at least one 2 and at least one 5, then eliminate the two combinations 2222 and 5555, and that answer would be 14.
The 1000th digit of pi is...9
the answer is 9
8
125
1 set
It is 120 if the digits cannot be repeated.
120 5-digit numbers can be made with the numbers 12345.
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
jfnvjsdkncjfdknvlakdjvbsadoihfcb shfvbcnsHLfc bnshJCbvjhbeshuyvbe b hdfbgehfgbwahucgbvfer fguy gyfuby uyr
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
ccsndf
12300
There are 625 of them - too many to list.
It is 2.
Well, darling, the digit in 12345 that has the same place value as the six in 67.89 is the one in the hundreds place. Both the six in 67.89 and the one in 12345 hold the same value of 600. So, there you have it, sweetie.