You can make 125 different 3-digit numbers if you're allowed to repeat a digit (for example, 113, or 545), and 60 if you're not. If repetitions are allowed, then there are 5 ways to choose each digit to be 1,2,3,4, or 5, so the total number of ways is 5*5*5 or 125. If no repetitions are allowed, there are 5 ways to choose the first digit, but only 4 ways left to choose the second (for a total of 5*4=20 ways to choose the first two digits), because it can't be the same as the first. Then you have eliminated two choices for the third digit, so there are only 3 ways to choose it, for a total of 5*4*3=60 different 3-digit numbers.
2+3+9=14 9+_+8=17+8=25 25-14=11
With each digit having only 2 possibilities, the answer is 2 to the 4th power, which is 16. The 4 is because there are 4 digits. Think about the binary numbers 0000 to 1111, there are 2 possibilities for each digit. If your constraint is that the digits must have at least one 2 and at least one 5, then eliminate the two combinations 2222 and 5555, and that answer would be 14.
The 1000th digit of pi is...9
8
the answer is 9
125
1 set
It is 120 if the digits cannot be repeated.
120 5-digit numbers can be made with the numbers 12345.
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
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If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
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There are 625 of them - too many to list.
The first digit may be any of 5 possibilities. The second digit may not be same as first, so only 4 possibilities. Likewise 3rd, 4th, and 5th digits may be chosen from only 4 possibilities. All together: 5*4*4*4*4 = 1,280 numbers.
It is 2.
If the two must be different digits, then there 20 possibilities. If they can be the same one, then there are 25 possibilities.