The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2.
5
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The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2.
5 × 4 × 3 × 2 = 120 possible numbers
1 set
125
There are 60480 numbers.
There are 5! = 120 such numbers.
90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.