The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2.
5
1 set
125
There are 60480 numbers.
90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.
There are 5! = 120 such numbers.
1 set
It is 120 if the digits cannot be repeated.
To form a five-digit number using the digits 1, 2, 3, 4, and 5, each digit must be used exactly once. Since there are 5 unique digits, the total number of different five-digit numbers that can be formed is given by the factorial of the number of digits, which is 5! = 120. Therefore, 120 different five-digit numbers can be formed using the digits 12345.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
jfnvjsdkncjfdknvlakdjvbsadoihfcb shfvbcnsHLfc bnshJCbvjhbeshuyvbe b hdfbgehfgbwahucgbvfer fguy gyfuby uyr
125
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
There are 625 of them - too many to list.
If the two must be different digits, then there 20 possibilities. If they can be the same one, then there are 25 possibilities.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
500
24