277612920, but only if any number (including 9) can appear more than once.
It will probably depend on the dividend (the number to be divided)
-12 = x+9 x+9 -9 = -12 -9 x = -21
.999 repeating = 1So 1.0think of it as7/9 = .777...8/9 = .888...9/9 = .999... 9/9 = 1
1 gram fat produce 9 calories i.e. 37.7 kJ
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
A regular octadecagon (an eighteen sided polygon) would have nine diagonals.
It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
Plug 9 as n in this formula: n(n-3)/2
The formula for the number of diagonals that an N-sided polygon has is# diagonals = N(N-3)/2N(N-3)/29(N-3)/29*(9-3)/29*6/2 = 54/227
8+7+6+5+4+3+2+1 = 36 diagonals
A six sided hexagon has nine diagonals.
9
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9