The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon.
So: 0.5*(81-27) = 27 diagonals
A 9-sided polygon, is named 'Nonagon'. The number of diagonals are '9' From any one node, to the centre of the opposite side. Since there are 9 nodes and 9 lines, then there will be 9 diagonals.
277612920, but only if any number (including 9) can appear more than once.
It will probably depend on the dividend (the number to be divided)
To convert tons of water to barrels, you first need to know that 1 ton of water is approximately equal to 7.48 barrels. Therefore, for 9 tons of water, you would multiply 9 by 7.48, which equals about 67.32 barrels. Thus, 9 tons of water is roughly 67 barrels.
-12 = x+9 x+9 -9 = -12 -9 x = -21
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
A 9-sided polygon, is named 'Nonagon'. The number of diagonals are '9' From any one node, to the centre of the opposite side. Since there are 9 nodes and 9 lines, then there will be 9 diagonals.
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
A regular octadecagon (an eighteen sided polygon) would have nine diagonals.
It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
Plug 9 as n in this formula: n(n-3)/2
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
The formula for the number of diagonals that an N-sided polygon has is# diagonals = N(N-3)/2N(N-3)/29(N-3)/29*(9-3)/29*6/2 = 54/227
8+7+6+5+4+3+2+1 = 36 diagonals
A six sided hexagon has nine diagonals.
9
7