As there is no system of equations shown, there are zero solutions.
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I regret that I can see no function shown.
The question cannot be answered because:there is no symbol shown between 2y and x,there is no information on the feasible region.The question cannot be answered because:there is no symbol shown between 2y and x,there is no information on the feasible region.The question cannot be answered because:there is no symbol shown between 2y and x,there is no information on the feasible region.The question cannot be answered because:there is no symbol shown between 2y and x,there is no information on the feasible region.
The cube-root of 6 is 1.817120593, to as many decimal places as are shown.
Points: (-4, 50 and (1, -5) Slope: -2 Equation works out as: y = -2x-3 Therefore it is C if you meant: y = -2x-3
The equation for the gradient of a linear function mapped in a two dimensional, Cartesian coordinate space is as follows.The easiest way is to either derive the function you use the gradient formula(y2 - y1) / (x2 - x1)were one co-ordinate is (x1, y1) and a second co-ordinate is (x2, y2)This, however, is almost always referred to as the slope of the function and is a very specific example of a gradient. When one talks about the gradient of a scalar function, they are almost always referring to the vector field that results from taking the spacial partial derivatives of a scalar function, as shown below.___________________________________________________________The equation for the gradient of a function, symbolized ∇f, depends on the coordinate system being used.For the Cartesian coordinate system:∇f(x,y,z) = ∂f/∂x i + ∂f/∂y j + ∂f/∂z k where ∂f/(∂x, ∂y, ∂z) is the partial derivative of f with respect to (x, y, z) and i, j, and k are the unit vectors in the x, y, and z directions, respectively.For the cylindrical coordinate system:∇f(ρ,θ,z) = ∂f/∂ρ iρ + (1/ρ)∂f/∂θ jθ + ∂f/∂z kz where ∂f/(∂ρ, ∂θ, ∂z) is the partial derivative of f with respect to (ρ, θ, z) and iρ, jθ, and kz are the unit vectors in the ρ, θ, and z directions, respectively.For the spherical coordinate system:∇f(r,θ,φ) = ∂f/∂r ir + (1/r)∂f/∂θ jθ + [1/(r sin(θ))]∂f/∂φ kφ where ∂f/(∂r, ∂θ, ∂φ) is the partial derivative of f with respect to (r, θ, φ) and ir, jθ, and kφare the unit vectors in the r, θ, and φ directions, respectively.Of course, the equation for ∇f can be generalized to any coordinate system in any n-dimensional space, but that is beyond the scope of this answer.