Pre-calculus is supposed to be a stringent review of trig and algebra in preparation for calculus. So, pre-calculus, I would say.
Simple answer: Calculus involves derivation and integration, precal doesn't. Pre calculus gives you some of the algebraic, geometric and trigonometric understanding that is required to comprehend the concepts in calculus. Without the knowledge from precal, calculus would not be easily understood, as it is taught in schools today.
You must have a strong basis in Algebra, Algebra II, Geometry and Trigonometry. Usually high schools offer a pre-Calculus course which is somewhat of a conglomeration of the aforementioned courses. Then you would move into differential calculus, integral calculus, vector (multi-variable) calculus, and finally differential equations, which is considered to be at the top of the hierarchy of the calculus courses. So take Algebra, Algebra II, Geometry and Trigonometry to get your strong foundation before begining the calculus sequence.
Nocturia
I think by "regular calculus" it is meant simple derivatives and integrations. Regular calculus would be first year calculus probably not including multi-variable calculus or calculus of variations or vector calculus. Wikipedia gives a good explanation of calculus. If you want to sound smart, call it "The Calculus". It is the study of the rate of change (how things change, in relation to other things, often time) In most Universities, regular calculus are the standard analysis of Calculus, concentrating more on the application of it rather than the concept. in comparison is either called "advanced calculus" or in my U, "Honours Calculus" which takes analysis to a whole new level. Both first year course, but the advanced one concentrates on the understanding of concepts, theorems rather than applications alone. It comes in the form of "mathematical proof". Regular Calculus does proofs too, but not as often. --------------------------------------------- Regular calculus is most probably calculus taught in high school or university level, which is simple, mostly single-variable calculus. But then, there are also different calculi called non-Newtonian calculi. These are the non-standard, non-regular calculi, in which different operators are defined. For example, "regular calculus" might mean an additive calculus (where the integral is defined by adding up extremely small pieces), while an integral in multiplicative calculus might involve multiplying infinitely many pieces close to 1.
Surface area of cell is divided volume of cell to get surface to volume ratio . If surface area is 8 cm2 and volume is 2 cm2 . The ratio would be 4:1 .
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
To calculate the surface area to volume ratio, simply divide the surface area of the object by its volume. This ratio is commonly used in science to understand how efficiently an object exchanges materials with its environment, with a higher ratio indicating better surface area for exchange relative to its volume.
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
Multiply the surface area by the volume Also stop cheating ur hw
It would help to know why what!
The sphere has a surface area-to-volume ratio of 0.15m^-1, which means it has a relatively low surface area compared to its volume. This indicates a more compact shape. On the other hand, the right circular cylinder with a ratio of 2.2m^-1 has a higher surface area compared to its volume, suggesting it is more elongated or spread out.
surface area to volume ratio can be solved by solving the surface are of something and the volume of something then putting them togetherEXAMPLE: if it is a cube with 4 cm on each side it would be 6(4)^2 = 6(16)=96cm and volume would be 4^3= 64 so ratio would be 96:64 which can be simplified 3:2 or 3 to 2
hippopatamus
A spherical protist would have a higher surface area to volume ratio compared to a cylindrical protist of the same size. This is because a sphere has the smallest surface area for a given volume, making it more efficient in terms of nutrient exchange and waste removal.
The cell with the smallest size would have the greatest surface-to-volume ratio. As the size decreases, the surface area to volume ratio increases because the surface area decreases at a slower rate than the volume.