Divide the total surface area of the cell by the cell's volume.
Surface area of cell is divided volume of cell to get surface to volume ratio . If surface area is 8 cm2 and volume is 2 cm2 . The ratio would be 4:1 .
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
Density is the ratio of mass to volume. Thus, the density of an object is the mass of the object divided by its volume.
A cylindrical protist has a higher surface are to volume ratio. This is because of the physical properties of spheres (some rather complicated math proves that spheres hold the most volume for their area).
If the shape is a perfect sphere, then the ratio of surface area to volume will always be: 4πr2 / 4/3πr3 = 3/r If the volume = 500m3, then we can say: 500m3 = 4/3πr3 375m3 = r3 r = 5∛3 m So the ratio of surface area to volume on that sphere would be 3 / (5∛3 m), or: 3∛3/5m
Multiply the surface area by the volume Also stop cheating ur hw
surface area to volume ratio can be solved by solving the surface are of something and the volume of something then putting them togetherEXAMPLE: if it is a cube with 4 cm on each side it would be 6(4)^2 = 6(16)=96cm and volume would be 4^3= 64 so ratio would be 96:64 which can be simplified 3:2 or 3 to 2
well the answer for an orange and apples is 13 oranges and 8 apples the ratio would be 13:8 so measure the animal ad find the volume of the animal and put it as a ratio
Surface area of cell is divided volume of cell to get surface to volume ratio . If surface area is 8 cm2 and volume is 2 cm2 . The ratio would be 4:1 .
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
You cannot calculate volume of surface area. If you meant 20m3, then the volume would be 20,000 litres.
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
The answer will depend on shape in question.
It would help to know why what!
If the cell's surface-to-volume ratio got too small as a result of the volume increasing faster than the surface area, the cell would no tbe able to get the nutrients it needs to survive and would die.
The rate of diffusion would be faster for the right cylinder.