The first expression, y = 4, would be a horizontal line at y = 4.
The second expression can be found by setting y equal to zero and solving for x, and, likewise, setting x equal to zero and solving for y:
2x = 2 <=> x = 1, so coordinate is (1,0)
y = 2, so coordinate is (0, 2)
Now draw a line connecting those two points and beyond them.
3
-1
5
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
Yes, that is a shifted tanX graph, just as you would shift any graft.
-2
-2
That line is [ y = 2 cos(2x) ].
the line of symmetry would occur at x=0
Answer: You must switch all your letters and numbers around... to where your problem is y=-2x+2. Than after you get your answer, for the problem, Graph it... to graph it, you would take your b (+2) and find it on the graph, than you would take your m (-2) and find it on the graph, but! you must make sure it is a fraction so you will have to find two numbers and graph your second number, than make a STRAIGHT line on your point, all the way across your graph.
8
-2/3
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
3
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
(0,4) and (-2, 0)