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3x + 4y = 9 is an equation, a statement that states the two expressions 3x + 4y and 9 are equal. We like to know if there are any values of the variables x and y that will make the statement a true one. In our case, we're going to check if x = 2 and y = 5, will satisfy the given equation. In other words, if we substitute the corresponding values of x and y into the equation and the left side will equal to the right side, then (2, 5) is a solution. Otherwise, it's not. Check: 3x + 4y = 9; x = 2 and y = 5 3(2) + 4(5) =? 9 6 + 20 =? 9 26 = 9 False Therefore, (2, 5) is not a solution.
4 - 3y - y = 04 - 4y = 0add 4y to both sides4 = 4ydivide both sides by 4y = 1
First rearrange these simultaneous equations in the form of: 7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top equation remembering that a - - is equal to a plus. So, -4y - - 4y = 0 2x = 12 and therefore it follows that x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
27 + y = 42 - 4y so 5y = 15 making y = 3 and x = 6
x2 + y2 - 10x + 4y - 52 = 0 x2 - 10x + y2 + 4y = 52 Complete the square (x2 - 10x + 25) + (y2 + 4y + 4) = 52 + 25 + 4 (x - 5)2 + (y + 2)2 = 81 (x - 5)2 + (y - -2)2 = 92 This is the equation of a circle with center (5, -2), and radius 9.
5
....Well...if you mean 4y + 9 = 17, then the answer is 2.If you mean 4y - 9 = 17, then the answer is 6.5.
y = 6
y = 2 (4X2=8) +9 = 17
4y = 929 4y/4 = 929/4 y = 232.25
4y-9 = 15 4y = 15+9 4y = 24 y = 6
10y-3=4y+6 10y = 4y + 9 6y = 9 y = 9/6 y = 3/2 y = 1.5
4y+y=10 5y=10 y=2
4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
4y+6+9=4y+15
+3 or -3 4y^2=36 =>(4y^2)/4=36/4 =>y^2=9 =>sqrt(y^2)=sqrt(9) =>y=+3 or -3
4y + 7 < 3y + 9 4y - 3y < 9 - 7 y < 2