y = 2 (4X2=8) +9 = 17
To answer this question we need to first get the slope of the line 5x-4y=9 by rearranging it in the form of y=mx+b: 5x-4y=9 4y=5x-9 y=(5/4)x-9/4 Since the slope of parallel lines are negative reciprocals of each other, the negative reciprocal of 5/4 is -4/5, therefore the slope of a line parallel to the line 5x-4y=9 is -4/5
2x - 3y = -4x + 4y = -9from the second equation x = -9-4y , substitute it in the first equation.2(-9-4y)- 3y= -4-18-8y-3y = -4-18-11y = -4-11y = -4+18-11y = 14y = -14/11now, solve for x :x = -9-4yx = -9-4(-14/11)x = -43/11
y > 3 Treat the greater than sign [a bit] like an equals sign to solve: 4y - 3 > 9 ⇒ 4y > 12 [add 3 to each side] ⇒ y > 3 [divide each side by 4]
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
y = 2 (4X2=8) +9 = 17
4y + 3 >= -94y >= -9 + -34y >= -12y >= -12/4y >= -3
You need to add signs in, like + - and =, without out those, the question cannot be answered
y = 6
5
4y-9 = 15 4y = 15+9 4y = 24 y = 6
X=3 y=2 (3x3) + (4x2) = 17 9 + 8 = 17
4y + 7 < 3y + 9 4y - 3y < 9 - 7 y < 2
(3 - 4y)(3 + 4y)
4y+6+9=4y+15
8
9/17 does that.