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4z - 1 = 9

4z = 10 (add 1 to both sides)

z = 2.5 (divide both sides by 4)

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Q: If 4z-1 equals 9 what is z?
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X varies directly with y and inversely with z x equals 0.12 when y equals 12 and z equals 2 Find x when y equals 1200 and z equals 1?

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If xy plus y equals z then x equals?

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X varies directly with y and inversely with z x equals 0.25 y equals 10 and z equals 20 find x when y is 20 and z is 10?

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What is the x- value of x-2y plus z equals -9 3y-2z equals 4 2x plus y plus 5z equals -5?

x-(x-2y)+z=-9 3y-2z=4 2x+y+5z=-5 x-(x-2y)+z=-9 --distribute negative through bracket--> x-x+2y+z=-9 x-x+2y+z=-9 --combine like terms (x)--> 2y+z=-9 2y+z=-9 --isolate z--> z=-9-2y substitute z into second equation: 3y-2(-9-2y)=4 --multiply -2 through bracket--> 3y+18+4y=4 3y+18+4y=4 --subtract 18 from both sides--> 3y+4y=-14 3y+4y=-14 --combine like terms--> 7y=-14 7y=-14 --divide both sides by 7--> y=-2 Substitute value of y into simplified first equation: z=-9-2(-2) --multiply through the bracket--> z=-9+4 z=-9+4 --combine like terms--> z=-5 Substitute values of y and z into third equation: 2x+(-2)+5(-5)=-5 --multiply through brackets--> 2x-2-25=-5 2x-2-25=-5 --combine like terms--> 2x-27=-5 2x-27=-5 --add 27 to both sides--> 2x=22 2x=22 --divide both sides by 2--> x=11 x=11, y=-2, z=-5


X varies directly with y and inversely with z x equals 125 when y equals 5 and z equals 4 Find x when y equals 4 and z equals 5?

Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100