x-(x-2y)+z=-9
3y-2z=4
2x+y+5z=-5
x-(x-2y)+z=-9 --distribute negative through bracket--> x-x+2y+z=-9
x-x+2y+z=-9 --combine like terms (x)--> 2y+z=-9
2y+z=-9 --isolate z--> z=-9-2y
substitute z into second equation:
3y-2(-9-2y)=4 --multiply -2 through bracket--> 3y+18+4y=4
3y+18+4y=4 --subtract 18 from both sides--> 3y+4y=-14
3y+4y=-14 --combine like terms--> 7y=-14
7y=-14 --divide both sides by 7--> y=-2
Substitute value of y into simplified first equation:
z=-9-2(-2) --multiply through the bracket--> z=-9+4
z=-9+4 --combine like terms--> z=-5
Substitute values of y and z into third equation:
2x+(-2)+5(-5)=-5 --multiply through brackets--> 2x-2-25=-5
2x-2-25=-5 --combine like terms--> 2x-27=-5
2x-27=-5 --add 27 to both sides--> 2x=22
2x=22 --divide both sides by 2--> x=11
x=11, y=-2, z=-5
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x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
x2y = k (constant) so 36 x 2 ie 72 is the constant. If x = 3 then y = 72/9 = 8
(2x)ysquared
You will get nonsense. You cannot plug x2y + 4 into anything!
It is -2y + x2y - 8, which is an expression that cannot be simplified further, not can it be evaluated.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
4 (apples) plus 3 (apples) = 7 (apples). 4 (cows) + 3 (cows) = 7 (cows) 4 (x2y) + 3 (x2y) = 7 (x2y)
Whooop!
(b - x)(ab - xy)
(x2 - 2)(y - 3)
The coefficient is 6.
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
4
3x3 - x2y + 12x - 4y = x2*(3x - y) + 4*(3x - y) = (x2 + 4)*(3x - y)