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Q: What is the value of y if 5y plus 8 equals 7y?

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5y+8=7y subtract 5y from each side , 5y+8=7y -5y -5y 8=2y /2 /2 4=y

5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7

2y+5y=10 7y=10 y=10/7

y = 14

7y + 4 = 5y - 6Subtract 4 from each side:7y = 5y - 10Subtract 5y from each side:2y = -10Divide each side by 2:y = -5

(5, 1)

6y=5y+2y 6y=7y that does't work its unequal -

(3,7)

The value of x is 11, and the value of y is 8.

7y - 6 = 5y - 147y - 5y = 6 - 142y = -8y = -8 ÷ 2y = -4

2y - 7 + 5y = 0 Collecting like terms together, 7y - 7 = 0 or 7y = 7 So that y = 1

The lines intersect at (3, 5)

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