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Q: What is x squared plus 2xy plus y squared?

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(x+y)2 = x2 + 2xy + y2

If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx

(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2

2x squared plus 2x plus xy plus y or 2x(x+1) + y(x+1) or (x+1)(2x+y)

Assuming y' is dy/dx, y = x^4/4 + yx^2

Related questions

Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0

(x+y)2 = x2 + 2xy + y2

2(x - 1)(2x + y)

3x2+6xy+3y2= 3(x2+2xy+y2)= 3(x+y)2

You can expand (x + y)2 into x2 + 2xy + y2

(x - y)2 = x2 - 2xy + y2

That would be very hard to answer, because it's not. (x + y)2 = x2 + y2 + 2xy

If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx

2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+

(3x - y)(x + y)(3x - y)(x + y)

(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2

Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2

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