(x+y)2
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(x+y)2 = x2 + 2xy + y2
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
Assuming y' is dy/dx, y = x^4/4 + yx^2
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