two real
-4
Take the derivative of the function and set it equal to zero. The solution(s) are your critical points.
You cannot have a simultaneous equation: you must have 2 or more equations for there to be any simultaneity.The simplest method to solve them is to invert the matrix of coefficients but this requires you to know matrix algebra and the question suggests tha you are not that advanced.In that case, express any one of the variables in terms of the other two. Substitute the resulting expression in the other equation(s). Repeat until you have only one variable. Find its value and substitute in the previous equation. That will then enable you to find a second variable. And so on.
It is a continuous line whose shape depends upon what expression it is meant to represent.The equation y = x would be a straight line passing through (0,0) and all the other points where the x and y co-ordinates were equal, including negative ones such as (-11,-11).But if the equation has x squared in it the shape would be a parabola, while the graph of an equation with y cubed in it would have something like an S shape in it. More complex equations could produce many differently shaped lines.
2mn - 2mt + 2sn - 2st = 0Divide both sides of the equation by 2:mn - mt + sn - st = 0m (n - t) +s (n - t) = 0(m + s) (n - t) = 0That's as far as you can go with the information given.
If the discriminant is negative, the equation has no real solution - in the graph, the parabola won't cross the x-axis.
The solution to an equation consists of the value (or values) of all the variables such that the equation is true when the variable(s) take those values.
7-4-14
The chemical equation is: (K+ + I-)(aq) + (Ag+ + [NO3]-)(aq) --> AgI (s) + (K+ + [NO3]-)(aq) or The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The complete balanced equation is Pb(NO3)2 (aq) + K2SO4 (aq) -> 2 KNO3 (aq) + PbSO4 (s). The total ionic equation is Pb+2 (aq) + SO4-2 -> PbSO4 (s).
b2 - 4ac (whatever that 4's sign is it is positive when squared ) (4)2 - 4(2)(- 9) 16 + 72 = 88 ===============Two real roots.
The ionic equation would usually be written as: Pb+2 (aq) + SO4-2 (aq) -> PbSO4 (s)
The chemical equation is:2 (OH)- + Pb(2+) = PbOH)2(s)
The chemical equation is:2 (OH)- + Pb(2+) = PbOH)2(s)
Mg(s) + 2AgNO3(aq) _> Mg(NO3)2(aq) + 2Ag(s)
S. Vadera has written: 'Learning after trees by incorporating linear discriminant analysis'
1. Add a small quantity of the FeCl3 solution into the Na2S(aq.). 2FeCl3+3Na2S=2FeS↓+6NaCl+S↓ the following is the ionic reaction equation 2Fe3+ + S2- = 2FeS↓+ S↓ 2. Add a small quantity of the Na2S solution into the FeCl3(aq.) 2FeCl3 + Na2S =2FeCl2 + 2NaCl + S↓ the following is the ionic reaction equation 2Fe3+ + S2- = S↓ + 2Fe2+