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integration by parts. Let u=lnx, dv=xdx-->du=(1/x)dx, v=.5x^2. Integral of (xlnxdx)=lnx*.5x^2-integral of .5x^2(1/x)dx=lnx*.5x^2-integral of .5xdx=lnx*.5x^2-(1/6)x^3. That's it.

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7y ago

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(1/4)(2 ln x - 1) + CThis can be obtained using integration by parts.

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8y ago
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The integral is x^2/4*[2*ln(x) - 1] + c

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8y ago
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Q: Integral of xlnxdx
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