Greater than, as four is more than zero.
3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
2x - 3x - 4 = 0 -x - 4 = 0 -x = 0 + 4 -x/-1 = 4/-1 x = -4
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
x=2, 3, 4...
greater than
0 is less than 4 but 0 is greater than -4
No. Zero is less than 4.
0
0 <= x <= 6 gives -1 <= Y <= 14.
1-4 equal less than and greater than = -3
p is greater than or equal to 4.
a is greater than or equal to 3
25
No. If x greater than or equal to 4 it must be 4 or higher; negative 4 is lower than 4
-5, -4, -3, -2, -1, 0 , 1, 2, ...
-2