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3x2 plus 8x plus 4 has two complex roots?
3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
What is the vertex for the parabola y equals x squared plus 4x plus 5?
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
X2 - 3x - 4 equals 0?
x2 - 3x - 4 = 0 so (x+1)(x-4) = 0, so x+1 = 0 and x-4 = 0, so x = -1 or 4
The sum of four consecutive even integers is the same as the least of the integers Find the integers?
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
If the replacement set is the set of integers find the solution set for the inequality x plus 11 greater than 12?
x=2, 3, 4...
