3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
x2 - 3x - 4 = 0 so (x+1)(x-4) = 0, so x+1 = 0 and x-4 = 0, so x = -1 or 4
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
x=2, 3, 4...
greater than
Yes, 0 is less than 4. In mathematical terms, 0 is on the left side of 4 on the number line, indicating that it is smaller. Additionally, the inequality symbol "<=" represents "less than or equal to," meaning that 0 is also equal to 4.
No. Zero is less than 4.
0
0 <= x <= 6 gives -1 <= Y <= 14.
1-4 equal less than and greater than = -3
p is greater than or equal to 4.
a is greater than or equal to 3
25
depends, when c>0, yes. when c=0 it's equal 4*0=0 and when c<0 it is smaller, because c=4: 4*-2=-8 and -8 is smaller than -2
-5, -4, -3, -2, -1, 0 , 1, 2, ...
3 multiples of 4 that is greater than 0 is 8,12, and 16.