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3x^2 + 8x + 4 = (x+2) (3x+2)

x = -2

x = -2/3

So there are no complex roots, they are real.

You can test this by b^2 - 4ac

if greater than 0, it is real

if equal, there will be 2 identical roots.

if less than 0 you get imaginary roots.

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Q: 3x2 plus 8x plus 4 has two complex roots?
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