3x^2 + 8x + 4 = (x+2) (3x+2)
x = -2
x = -2/3
So there are no complex roots, they are real.
You can test this by b^2 - 4ac
if greater than 0, it is real
if equal, there will be 2 identical roots.
if less than 0 you get imaginary roots.
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It has two complex roots.
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Any number greater than 0 has two square roots, a positive square root and a corresponding negative square root. Rounded to two decimal places, the square roots of 200 are ±14.14.
The question is ambiguous and two possible answers are given below: 2x2 - x2 = x2 or (2x)2 - x2 = 4x2 - x2 = 3x2
it equals x1 it equals x1