3x^2 + 8x + 4 = (x+2) (3x+2)
x = -2
x = -2/3
So there are no complex roots, they are real.
You can test this by b^2 - 4ac
if greater than 0, it is real
if equal, there will be 2 identical roots.
if less than 0 you get imaginary roots.
It has two complex roots.
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Any number greater than 0 has two square roots, a positive square root and a corresponding negative square root. Rounded to two decimal places, the square roots of 200 are ±14.14.
The question is ambiguous and two possible answers are given below: 2x2 - x2 = x2 or (2x)2 - x2 = 4x2 - x2 = 3x2
x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
two complex
two negative
It has two complex roots.
3x + 5x + 10 = 0a = 3, b = 5, c = 10D = b - 4ac = 25 - 120 = -95Since D < 0, we have two conjugate complex roots.√D = √-95 = i√95x = (- b ± √D)/2ax = -5/6 + [(√95)/6]i or x = -5/6 -[(√95)/6]i
The answer will depend on the form of the fourth root. Positive real numbers will have two fourth roots which are real and two that are complex. Complex numbers will have four complex roots. However, none of these can be "simplified" in the normal sense of the term.
Two of the four roots are 1.8212 and -1.8212 (approx). The other two roots are complex numbers.
3x2 + 2x + 1 this can not be factor and receive whole numbers. you need to use the quadratic equation. your answer will also have a complex number in it.the complex number will be sqrt of -1 which is equal to i 2+sqrt(-8) / 6 and 2-sqrt(-8) / 6 these two are your answers.
Whether the equation has 2 distinct roots, repeated roots, or complex roots. If the determinant is smaller than 0 then it has complex roots. If the determinant is 0 then it has repeated roots. If the determinant is greater than 0 then it has two distinct roots.
Twice. Between negative two and negative one.
A quadratic function can have up to two roots. Depending on the discriminant (the expression under the square root in the quadratic formula), it can have two distinct real roots, one repeated real root, or no real roots at all (in which case the roots are complex). Therefore, the total number of roots, considering both real and complex, is always two.
If the discriminant is negative, the roots will be two unreal complex conjugates. If the discriminate is positive the roots will be real.
3x2 + 6x is ONE expression. A common factor is a factor that is COMMON to two (or more) expressions - not just one. An alternative answer: 3x can be factored out of both of those.