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Q: Is 5. 4 a solution to this system of equations?

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7

It is a simultaneous equation and its solution is x = -1 and y = -5

The value of x is the solution of 4 3x plus 5 17 is given as follows . 12 x + 5 =17. 12x =12. Hence , x=1. ThusThe value of x is the solution of 4 3x plus 5 17 is 1.

Solve this simultaneous equation using the elimination method after rearraging these equations in the form of: 3x-y = 5 -x+y = 3 Add both equations together: 2x = 8 => x = 4 Substitute the value of x into the original equations to find the value of y: So: x = 4 and y = 7

7x - 9y = 35-3x + 6y = -15 (divide the second equation by 3, after that multiply it by 7)7x - 9y = 35-7x + 14y = -35 (add both equations)5y = 0 (divide both sides by 5)y = 07x - 9y = 35 (substitute 0 for y)7x = 35 (divide both sides by 7)x = 5Thus the solution of the given system of the equations is x = 5 and y = 0.

Related questions

It is (5 and minus1).

That of course will depend on what system of equations are they which have not been given

Tell whether the ordered pair (5, -5) is a solution of the system

7

Without any equality signs the given expressions can't be considered as equations.

One way is to look at the graphs of these equations. If they intersect, the point of intersection (x, y) is the only solution of the system. In this case we say that the system is consistent. If their graphs do not intersect, then the system has no solution. In this case we say that the system is inconsistent. If the graph of the equations is the same line, the system has infinitely simultaneous solutions. We can use several methods in order to solve the system algebraically. In the case where the equations of the system are dependent (the coefficients of the same variable are multiple of each other), the system has infinite number of solutions solution. For example, 2x + 3y = 6 4y + 6y = 12 These equations are dependent. Since they represent the same line, all points that satisfy either of the equations are solutions of the system. Try to solve this system of equations, 2x + 3y = 6 4x + 6y = 7 If you use addition or subtraction method, and you obtain a peculiar result such that 0 = 5, actually you have shown that the system has no solution (there is no point that satisfying both equations). When you use the substitution method and you obtain a result such that 5 = 5, this result indicates no solution for the system.

It is a simultaneous equation and its solution is x = -1 and y = -5

-10

(-4,-5)

Without any equality signs the given terms can't be considered to be equations.

Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5

One solution 2x+y =5 x+2y=4 multiply 1st eq by 2 rhen subtract: 4x+2y = 10 x + 2y = 4 3x = 6 x = 2 plug x into any of the above two equations and solve y = 1

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