Yes it is, where r is the radius
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x = 9/2 or x = -2 Solved by using the quadratic equation formula.
f(x) = 2*(x-3)*(x+2)/(x-1) for x ≠1
Correct form. 2X^2 - 2X - 1 = 0 - b +/- sqrt(b^2 - 4ac)/2a quadratic formula a = 2 b = - 2 c = -1 -(-2) +/- sqrt[(-2)^2 - 4(2)(-1)]/2(2) 2 +/- sqrt( 4 + 8)/4 2 +/- 2sqrt(3)/4 exact answer, less final factoring
Use the quadratic formula, with a = 1, b = -3, c = 2.
x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2