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Correct form. 2X^2 - 2X - 1 = 0
- b +/- sqrt(b^2 - 4ac)/2a
a = 2
b = - 2
c = -1
-(-2) +/- sqrt[(-2)^2 - 4(2)(-1)]/2(2)
2 +/- sqrt( 4 + 8)/4
2 +/- 2sqrt(3)/4
exact answer, less final factoring
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What are the values of x in this quadratic equation 2x squared-x-5 equals 0?
2x2 - x - 5 = 0 x = [1 +/- sqrt(1 + 40)]/4 = [1 +/- sqrt(41)]/4 = -1.35078 and 1.85078
What is x when 2x2 - x - 6 equals 0?
2 X 2 - x - 6 = 04 -6 - x = 0- x = 2x = -2Another contributor's answer:This appears to be a quadratic equation question in form of:2x2-x-6 = 0When factorised:(2x+3)(x-2) = 0Therefore: x = -3/2 or x = 2
What is x squared minus 2x plus 5 equals 0?
It is a quadratic equation with one unknown variable, x which has no real roots.
How do you solve for x in the equation x2-2x-2 equals 0?
To solve for x in the equation x2 - 2x - 2 = 0, use the quadratic equation, that is: For 0 = ax2 + bx + c, the roots (values of x) are defined as: x = [-b +/- sqrt(b2 - 4ac) ] / 2a (If that's hard to understand, google "quadratic formula"). It works out to x = 2.73, -0.73.
I need An answer for 2x square -3x-2 0?
there is no problem with this quadratic equation it's 2x square - 3x -2 = 0 I need an answer. where it says square there should be a little 2 at the top corner of the 2x to make it 2x square thanks If you can't factor it easily then use the quadratic equation: The two solutions are: 2 & -.5
