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LaoNot with the default definitions of the domain (the real numbers) and range (reals greater than or equal to -3). With these definition the original function is many-to-one (except at one point) and so the inverse function - if it existed - would be one-to-many. A function cannot be one-to-many.
However, if you redefine the domain of the original function so that it is the non-negative reals, the function becomes one-to-one and so does have an inverse which is x = +sqrt(y + 3) - the principal square root of (y+3).
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What is the inverse function of fx equals 5x-24?
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What is the inverse function of y equals 3x-3?
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P x r equals 176. what is the inverse?
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What is the inverse function of y equals 7x plus 2?
First, this function is strictly increasing on the entire real line, so an inverse exist on the entire real line. We define inverse of function f, denoted f^-1 such that if y = f(x) then f^-1(y) = x Or to find the inverse, all is needed is to isolate x in terms of y. In this case, y = 7x + 2 7x = y - 2 x = (y - 2)/7 So the inverse is x = (y - 2)/7 What? You don't like function in terms of y? Well, they are just meaningless variables anyway, you can write whatever, in particular the inverse is y = (x - 2) / 7 (the x, y here are independent with the x, y above. If you are getting confused, write b = (a - 2)/7 where b is a function of a)
