Y = 1/X2 ==============Can it pass the line test? * * * * * That is not the inverse, but the reciprocal. Not the same thing! The inverse is y = sqrt(x). Onless the range is resticted, the mapping is one-to-many and so not a function.
No. A simple example of this is y = x2; the inverse is x = y2, which is not a function.
Y = X2 Inverse. Y = 1/X2 ======
Yes
Y=X^2 is a function for it forms a parabola on a graph.
Y = 1/X2 ==============Can it pass the line test? * * * * * That is not the inverse, but the reciprocal. Not the same thing! The inverse is y = sqrt(x). Onless the range is resticted, the mapping is one-to-many and so not a function.
No. A simple example of this is y = x2; the inverse is x = y2, which is not a function.
Y = X2 Inverse. Y = 1/X2 ======
y = x2 where the domain is the set of real numbers does not have an inverse, because the square root function is a one-two-two mapping (except at 0). Any polynomial with more than one root, over the reals, has no inverse. y = 1/x has no inverse across 0. But it is possible to define the domain so that each of these functions has an inverse. For example y = x2 where x is non-negative has the square root function as its inverse.
Yes. Think of y as being a function of x. y = f(x) = x2 + 1
Yes
No, it is not.
Y=X^2 is a function for it forms a parabola on a graph.
1 over x2 - 4 is the multiplicative inverse of x2 minus four 1/x2 - 4
The additive inverse of x2yz is -x2yz
Implicit: x2 + 2y = 5 Explicit : y = (5 - x2)/2
f(x) = x2 This describes a parabolic curve, with it's vertex at the point (0, 0)