-8
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No, because a quadratic involves a second power. Unless the y represents x^2, or some other x to the power of 2, it is not quadratic.
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
6x - 14 = 3x + 5Subtract 3x from each side: 3x - 14 = 5Add 14 to each side: 3x = 19Divide each side by 3: x = 19/3
x^2 - 6x + 6 = 0 Quadratic formula give (6 +/- sqrt(36 - 24))/2 ie 3 +/- (sqrt 12)/2 = 3 +/- 3.464/2 = 3 +/- 1.732 = 4.732 or 1.268
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
3x - 8 = 7 so x = 5