x^2 - 6x + 6 = 0 Quadratic formula give (6 +/- sqrt(36 - 24))/2 ie 3 +/- (sqrt 12)/2 = 3 +/- 3.464/2 = 3 +/- 1.732 = 4.732 or 1.268
3x - 12 = 10x - 15 - 6x -10 3x - 12 = 4x -25 3x + 13 = 4x 13 = 4x - 3x 13 = x None?
(x3-3x2+6x+5)/(x-2) = x2-x+4 remainder 13 or as x2-x+4+13/(x-2) It's difficult to show the workings out on this computer but division in algebra has a lot in common when doing long division with integers.
6x2 + 58x + 80 = 02(40 + 29x + 3x2) = 02((8 + x)(5 + 3x)) = 0, ignore 28 + x = 0 => x = -85 + 3x = 0 => 3x = 5 => x= 1.666666....x = {-8, 1.66....}
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
the answer is (3x-2)(9x squared+6x+4)
{-1,7}
It is: 3x2+6x-11 = 0
x-8
(6x - 1)(6x - 1)
6x - 4y
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
6x^2 -13x+6 = (3x-2)(2x-3) when factorized
That factors to (x - 5)(x - 1)
(4x - 3)(2x + 3)
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
3x(2x + 1)
The answer is 35. 2x2-6x+15 2(-2)2-6(-2)+15 8+12+15 35. And this is not calculus...