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How can you use the fact 11 x 5 equals 55 to solve 11 x 6?
Multiplication is simply repetitive addition. For instance, the expanded form of 2 * 3 is: 2 + 2 + 2, or 3 + 3. The expanded form of 5 * 6 is: 5 + 5 + 5 + 5 + 5 + 5, or 6 + 6 + 6 + 6 + 6. From the information above, it is evident that 11 * 5 = 11 + 11 + 11 + 11 + 11, and 11 * 6 = (11 * 5) + 11 So, substitute 55 for 11 * 5: 11 * 6 = 55 + 11 11 * 6 = 66
How many number between 400 and 500 which is exactly divisible by 12 15 and 20?
First, find the prime factors of 12,15,20:12=2*2*315=3*520=2*2*5Now, compute the LCM by multiplying the factors (count duplicates once):LCM=2*2*3*5=60Only the multiples of the LCM will be divisible by 12, 15, and 20:60,120,180,240,300,360,420,480,540...{420,480}
Evaluate 3x if x equals -2?
5
2x - 6 4?
2x-6=4 6+4=2x 10=2x 10/2=x 5=x x=5
How do you simplify this 4 over x plus 2 plus 6 over x plus 5?
Assume the expression is:4/(x + 2) + 6/(x + 5)Simplify this expression by combining the expressions altogether. Let's go step by step.Step 1: Determine the LCD of the expression.The LCD of the expression is (x + 2)(x + 5). Multiply the top and bottom of each fractional expression by whatever factor the denominator is missing!4/(x + 2) * (x + 5)/(x + 5) + 6/(x + 5) * (x + 2)/(x + 2)Step 2: Combine the expression and simplify.(4(x + 5) + 6(x + 2))/((x + 2)(x + 5))= (4x + 20 + 6x + 12)/((x + 2)(x + 5))= (10x + 32)/((x + 2)(x + 5))
