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3x+12 = 18 3x = 18-12 3x = 6 x = 2
If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
3x - 2 = 19Add 2 to each side:3x = 21Divide each side by 3:x = 7
(x - 3x - 6) / 6 = (3x + 2) / 2 ∴2(3x + 2) = 6(3x + 2) ∴6x + 4 = 18x = 12 ∴12x = -8 ∴x = -2/3
3x - y = -1 x = -2 3(-2) -y = -1 -6 - y = -1 -y = 5 y = -5