3x+12 = 18 3x = 18-12 3x = 6 x = 2
If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
3x - 2 = 19Add 2 to each side:3x = 21Divide each side by 3:x = 7
(x - 3x - 6) / 6 = (3x + 2) / 2 ∴2(3x + 2) = 6(3x + 2) ∴6x + 4 = 18x = 12 ∴12x = -8 ∴x = -2/3
3x - y = -1 x = -2 3(-2) -y = -1 -6 - y = -1 -y = 5 y = -5
explain how to evaluate an algebraic expression for given variables. how would we evaluate the expression "3x-4y+9" when x=2and y=5?
Given a value of x, find the value for -3x + 2
for x = -2: x2 = 4, -5x2 = -20; 3x = -6 giving -20 - (-6) = - 20 + 6 = -14.
3x + 7 = 3(-3) + 7= -9 + 7= -2
if f(x) = 3x + 2 and you're looking for f(2), just plug in 2 for x: f(2) = 3(2) + 2 = 6 + 2 = 8.
When x = 2, 3x + 5 = 11.
3x+12 = 18 3x = 18-12 3x = 6 x = 2
x + 2 = 3x-1 -2x = -3x = 1,5
x-2=3x+1 x=3x+1+2 x-3x=3 -2x=3 x=-3/2
3x-2=x+8 (+2) 3x=x+10 (-x) 2x=10 (/2) x=5
3x - 7 = 2 3x = 9 x = 3
-3x + 2 = -7 - 2 -2 -3x = -9 so x = 3