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Why do imaginary solutions come in pairs?
Yes, they do. If a+bi is a solution, a-bi is also a solution.
What is the codomain?
The codomain of a function is an arbitrary set that contains all the images of a function. Thus, the function defined by f(x) = cos x + i sin x might be said to have codomain C, or the set of all complex numbers. The range is much more specific: it is the set of all the images, and nothing more. In this case, the range is {a + bi = z in C: |z| = 1}.
What is a number that can be written in the form a plus bi where a and b are real numbers?
A number of the form (a + bi) is a complex number.
A number written in the form a plus bi is called a number?
complex
What is a number written in the form a plus bi is called a what number?
It is called a complex number.
What does sap bi normally refer to?
SAP BI is referring to SAP Business Intelligence solutions which simplify data manipulation. It's a program used by corporations to simplify business functions.
Is a complex number a number that can be written in the form a plus bi where a and b are real numbers?
Yes, a+bi is standard form for a complex number. The numbers (a) and (b) are both real and i is √(-1)
The complex conjugate of a plus bi is?
a-bi a(bi)-1 not negative bi
What is a number of the form a plus bi where a is the real part and b is the imaginary part?
a complex number
Find the reciprocal of the complex number 3 plus 2i Give your answer in the usual a plus bi form?
It is 3/13 - 2/13*i
How do you simplify complexed fractions?
You multiply the numerator and the denominator of the complex fraction by the complex conjugate of the denominator.The complex conjugate of a + bi is a - bi.
How do you simplify a complex fraction?
You multiply the numerator and the denominator of the complex fraction by the complex conjugate of the denominator.The complex conjugate of a + bi is a - bi.
What is the reciprocal of a plus bi if a2 plus b2 equals 1?
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
Give the three address code of the expression a equals bi plus cj?
plus a, bi, cj
