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The reciprocal of a + bi is a - bi:
1/(a + bi) since the conjugate is a - bi:
= 1(a - bi)/[(a + bi)(a - bi)]
= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:
= (a - bi)/(a2 + b2) since a2 + b2 = 1:
= a - bi/1
= a - bi
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If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
A2 plus b2 equals c2 is an example of?
Pythagorean Theorem
If a2 plus b2 equals c2 then the triangle is?
a right triangle
How do you solve a2 plus c2 equals b2 and a equals 10 and your c is 30?
All you need to do is substitute the given values of a and c into the equation, then solve for c: a2 + c2 = b2 102 + 302 = b2 100 + 900 = b2 b2 = 1000 b = √1000 b = 10√10
If a2 plus b2 plus c2 - ab - bc - ca equals 0 then prove a equals b equals c?
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
Why is the Pythagorean therm a2 plus b2 equals c2 not a plus b equals c?
l a2 b2 is c2!!Its completely norma
A2 plus b2 equals c2 is an example of?
Pythagorean Theorem
If a2 plus b2 equals c2 then the triangle is?
a right triangle
What are the lengths of and A plus B in a right triangle if C equals 8?
A2 + B2 = C2 If C=8, then A2 + B2 = 64
What is the algebraic formula for a2 plus b2 equals c2?
You just typed it.
If a plus b plus c equals x plus y plus z then prove a2 plus b2 plus c2 equals x2 plus y2 plus z2?
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
How do you calucate a2 plus b2?
a2+2a2b+2ab2+b2
Who introduced a2 plus b2 equals c2?
Pythagoras' theorem for a right angle triangle.
How do you solve a2 plus c2 equals b2 and a equals 10 and your c is 30?
All you need to do is substitute the given values of a and c into the equation, then solve for c: a2 + c2 = b2 102 + 302 = b2 100 + 900 = b2 b2 = 1000 b = √1000 b = 10√10
If a2 plus b2 plus c2 - ab - bc - ca equals 0 then prove a equals b equals c?
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
CosA equals a2 plus c2 minus b2 by 2ac what is this formula?
This is known as the Cosine Rule.
