ex = x3
This has two solutions:
x = 4.5364...
and
x = 1.85718...
Plot the graph of each and you can see the intersections.
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How would you prove algebraically that the following function is one to one? f(x)= (x+3)^2 , x>= -3?
So, do you mean what is 5x+3=4x? If you do, I don't think that's algebraically possible, but I'm not sure. You have to have at least one more number without a variable on the 4x side for the equation to be solvable.
3x-2 = 2x+3 3x-2x = 3+2 x = 5
x+3=14 x+3-3 = 14-3 (subtract 3 from both sides to solve for x) x = 11
The variable is a. You can solve for it, like this: 8a - 9 = 7a - 6 8a = 7a + 3 8a - 7a = 3 a = 3