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Solve for x and y. ax plus by equals a-b bx-ay equals a plus b plus b?
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
How do you find the value of x in the following 10 times x 73?
You cannot solve an expression. You need an equation or inequality.You cannot solve an expression. You need an equation or inequality.You cannot solve an expression. You need an equation or inequality.You cannot solve an expression. You need an equation or inequality.
What is the distance between the z-intercept from the x intercept in the equation ax plus by plus cz plus d equals 0?
ax + by + cz + d = 0At the z-intercept, 'x' and 'y' are both zero.cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).At the x-intercept, 'y' and 'z' are zero.ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) issqrt[ (-d/a)2 + (-d/c)2 ] = sqrt (d2/a2 + d2/c2) = d sqrt(1/a2 + 1/c2)
How can you determine if an ordered pair is a solution to an equation?
plug the x coordinate in the x part of the equation and plug the y coordinate in the y's part of the equation and solve
What is the derivative of ax?
let f(x) = ax if a is a constant, then f'(x) = a if a is not constant, then f'(x) = ax' + a'x
Solve the equation ax-b equals c for x?
ax - b = c ax = b + c x = (b + c)/a
What is x as the subject what equation ax plus b equals cx plus d?
x = (d-a)/(a-c)
How do you solve for x using a quadratic equation?
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
How can we find the coordinates of x in the intersection of line and curve?
For example, the equation of a line: y = ax + b. the equation of a curve: y = cx2 + dx + e ax + b = cx2 + dx + e (solve for x)
What do you need to divide by to solve the equation of the form axb?
To solve an equation of the form ( ax = b ), you need to divide both sides of the equation by ( a ) (assuming ( a \neq 0 )). This gives you ( x = \frac{b}{a} ), isolating ( x ) on one side of the equation.
Solve for x and y. ax plus by equals a-b bx-ay equals a plus b plus b?
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
How do you rewrite a linear equation?
The answer depends on what form the equation is in and what form you want it in. The standard form is ax + by +c = 0 where x and y are variables and a, b and c are constants. There are also the 1-d equivalent: ax + b = 0 and 3-d equivalent: ax + by + cz + d = 0 and, equivalent equations in spaces with higher dimensions.
How do you find the y intercept of a linear relationship from an equation?
plug in a 0 for the "x" value of the equation, and solve it :D
What is the equation for cubic reflected over the x axis and vertical shift down 2?
A cubic function can be expressed in the form ( f(x) = ax^3 + bx^2 + cx + d ). To reflect this function over the x-axis, you negate it, resulting in ( f(x) = -ax^3 - bx^2 - cx - d ). To apply a vertical shift down by 2, you subtract 2 from the entire function, leading to the final equation: ( f(x) = -ax^3 - bx^2 - cx - (d + 2) ).
What is the distance between the z-intercept from the x-intercept in the equation ax by czd?
Before this question can be answered, you'll need to rewrite the equation in a legible manner. Do you mean: ax + by = czd? ax - by + cz = d? ax + by + czd? (not even an equation) Please use spoken words to express your question when the form won't accept symbols. For example, the first of those equations could be expressed as "a times x plus b times y equals c times z to the power of d".
How too solve linear equations?
First rearrange the linear equation to the form ax + b = cThen subtract b from both sides: ax = c - b Divide both sides by a: x = (c - b)/a
What is the first step in solving a quadratic equation of the form (ax plus b)2c?
The first step in solving a quadratic equation of the form ((ax + b)^2 = c) is to take the square root of both sides to eliminate the square. This gives you two possible equations: (ax + b = \sqrt{c}) and (ax + b = -\sqrt{c}). From there, you can isolate (ax) and solve for (x) by subtracting (b) and then dividing by (a).
