A cubic function can be expressed in the form ( f(x) = ax^3 + bx^2 + cx + d ). To reflect this function over the x-axis, you negate it, resulting in ( f(x) = -ax^3 - bx^2 - cx - d ). To apply a vertical shift down by 2, you subtract 2 from the entire function, leading to the final equation: ( f(x) = -ax^3 - bx^2 - cx - (d + 2) ).
If the equation is a(x-n)2+c, c causes the vertical shift. By setting the part in parenthesis, x-n, equal to 0, you can find the horizontal shift (x-n=0). I hope this helped :)
None.
To apply the given transformations to the equation ( y = x^3 ), we start with the reflection across the x-axis, which gives us ( y = -x^3 ). Next, we apply the horizontal shift of 8 units to the left, resulting in ( y = - (x + 8)^3 ). Finally, we apply the vertical compression by a factor of ( \frac{1}{7} ), leading to the final equation: ( y = -\frac{1}{7}(x + 8)^3 ).
A shift in which a plane figure moves vertically.
Assuming you mean that the pi is not within the sin(2pi), its a vertical shift of +pi
The equation of a sine wave is y A sin(Bx C) D, where A represents the amplitude, B is the frequency, C is the phase shift, and D is the vertical shift.
(x + 6)2 + (y - 9)2 = 3 The general formula for the equation of a circle is: (x + 'horizontal shift')2 + (y + 'vertical shift')2 = radius
(x + 6)2 + (y - 9)2 = 3 The general formula for the equation of a circle is: (x + 'horizontal shift')2 + (y + 'vertical shift')2 = radius
y=2/3cos(1.8b-5.2)+3.9
If the equation is a(x-n)2+c, c causes the vertical shift. By setting the part in parenthesis, x-n, equal to 0, you can find the horizontal shift (x-n=0). I hope this helped :)
A vertical shift is the vertical motion of a function on a graph through manipulation of the y-coordinates, while simultaneously leaving the x-coordinates unchanged. A horizontal shift is the opposite of a vertical shift, in that the function is moving horizontally by manipulating the x-coordinates and leaving the y-coordinates unchanged.
None.
yes
To apply the given transformations to the equation ( y = x^3 ), we start with the reflection across the x-axis, which gives us ( y = -x^3 ). Next, we apply the horizontal shift of 8 units to the left, resulting in ( y = - (x + 8)^3 ). Finally, we apply the vertical compression by a factor of ( \frac{1}{7} ), leading to the final equation: ( y = -\frac{1}{7}(x + 8)^3 ).
A shift in which a plane figure moves vertically.
Assuming you mean that the pi is not within the sin(2pi), its a vertical shift of +pi
To shift the graph of y = 4x + 7 down, you would subtract a constant from the equation. In this case, you would subtract 7 from the equation to shift it downward. The new equation would be y = 4x. This would shift the entire graph downward by 7 units along the y-axis.