For an equation of the form
ax² + bx + c = 0
you can find the values of x that will satisfy the equation using the quadratic equation:
x = [-b ± √(b² - 4ac)]/2a
Using the quadratic equation formula: x = 8.42 or x = -1.42
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
x2+3x+2=0 (x+2)(x+1)=0 x=-2 or -1
If you mean: x squared+9x+14 = 0 then by using the quadratic equation formula x = -2 or x = -7
Graph the equation then find the x intercepts.
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
With great difficulty because it is not a quadratic equation or even a quadratic expression.
The roots of the quadratic equation are the x-intercepts of the curve.
You can't because it is not a quadratic equation.
The quadratic formula cannot be used to solve an equation if the coefficient of the equation x square term is what?
Using the quadratic equation formula: x = 8.42 or x = -1.42
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
It can be solved by using the quadratic equation formula.
How you solve an equation that doesn't factor is to plug a quadratic equation's format; ax2+bx+c into the quadratic formula which is x=-b+square root to (b2-4ac)/2a.
By using the quadratic equation formula: x = -5 and x = 3
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.