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A = pi * r2 Take implicit derivative with regard to time for 'rate' type questions: dA/dt = 2 * pi * r * dr/dt dA/dt = 2 * pi * (3 mm) * (10 mm/s) = 60 pi mm2/s

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Q: Suppose that the radius of a circle is increasing at the rate of 10mms-1 what is the rate of change of the area of the circle when r 3mm?
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