A unit circle is in the coordinate plane where both axes are measured in real numbers. The imaginary circle is in the complex plane in which one axis (horizontal) measures the real component of a complex number and the other axis measures the imaginary component.
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The Unit Circle is a circle that has a radius of 1 and a center at the origin. If you look at the unit circle 90 degrees is at the point (0,1). Cosine is equal to the x value of a point on the Unit Circle. The line created to the point (0,1) on the unit circle when the degree is 90 is completely vertical, which in turn makes the x value 0 and thus, cosine of 90 = 0. Read more >> Options >> http://www.answers.com?initiator=FFANS
the only close answer i know is: eix = cos(x)+i*sin(x) where i is imaginary unit
This is a fairly straightforward trigonometry problem. I'll assume you were give tan(θ)=(-1) for 0o < θ < 360o in this situation. I strongly suggest you familiarize yourself with the unit circle. In this case, we are looking for a point on the circle where the slope between (0,0) and the point at θ is (-1). This occurs at 135o and 315o. Short Answer: θ = {135o, 315o}
"The basic difference between slides and flows is that slides initially move as a unit with little or no deformation within the sliding mass, whereas flows are thoroughly deformed internally during movement."-Alan E. Kehew 9Geology for engineers & Environmental Scientists)
On the unit circle sin(90) degrees is at Y = 1 and as that is on the Y axis X will equal = 0. Ask yourself. Where would 90 degrees be on a 360 degree circle? Straight up.