The first constraint implies x*y=363, while you are finding the minimum of x+3y. You can do this with multivariable calculus approaches, but I will assume the simplest method is desired and use single-variable calculus methods.
Since xy=363, y=363/x
Substitute this into x+3y, and you get:
f(x)=x+3(363/x)=x+1089/x
Since you have this function as a function of a single variable now, you can minimize it like any other single variable function.
f'(x)=1-1089x-2
by setting f'(x)=0, the solutions x=33 and x=-33 are found. x=-33 is an extraneous solution, since you are required to have positive numbers. So, you must investigate x=33 and confirm it is a minimum.
If x=33 is a minimum of f(x), then values less than x=33 will yield a negative value in f'(x), since the function f(x) must slope downward up until it reaches a minimum. Conversely, values greater than x=33 will yield positive values in f'(x).
1<33
f'(1)=-1088
-1088<0, so f'(1) is negative
40>33
f'(40)=511/1600
511/1600>0, so f'(40) is positive.
In a final summating statement:
Since the function f(x)=1-1089/x2 has a critical point at x=33 and since values less than x=33 result in negative values of f'(x) and values greater than x=33 result in positive values of f'(x), x=33 is a local minimum of f(x).
To get your final final answer:
x=33
y=363/x implies y=363/33=11
x=33,y=11
The set of non-negative integers includes zero: [0,1,2,3,4,...]. These are also called whole numbers. The set of positive integers does not include zero: [1,2,3,4...]. These are also called counting/natural numbers.
When the first derivative of the function is equal to zero and the second derivative is positive.
It would take a million seconds = 16666.667 minutes = 277.778 hours = 11.57 days approx. This assumes (a) that you can count 1 per second which may not be realistic for large numbers and (b) that you can count for that length of time without stopping.
The domain of a function, is the range of input values which will give you a real answer.For example the domain of x+1 would be all real numbers as any number plus 1 will be another real numberThe domain of x0.5 would be all positive numbers as the answer to square root of a negative number is not realNote:x0.5 means the square root of x* * * * *Not quite. A function is a one-to-one or many-to-one mapping from a set S to a set T (which need not be a different set). A function can be one whose domain is all the cars parked in a street and the range is the second character of their registration number.A mathematical function can have the complex field as its domain and range, so a real answer is not a necessary requirement for a function.
About 1,000,000,000 seconds I say it would take longer becasue it would take longer than 1 second to say eg. one million six hundred and twenty four thousand nine hundred and sixty five. So if you timed that for each number it would take a long time. Answer: Although lower numbers (1, 2, 3 etc.) can be said in a second or less, larger numbers like 999,999,999 take up to 5 seconds to say. Assuming that an average value would be 4 seconds the time required would be 4 billion seconds if you didn't stop or rest. This is the same as 127 years.
The two numbers are 10 and 14.
380
Subtract one from the other.If the answer is positive then the first is larger,if the answer is negative, then the second is larger.Rational numbers are numbers that can be expressed as fractions whereas irrational numbers can't be expressed as fractions.
Take two numbers. Throw (the first number) into a box (the second number) times. The total amount in the box is then the product of the two numbers.
The problem is complete. There is enough information there for it to be solved.
Have the second number be greater than the first.
Have the second number be greater than the first.
30 - 31 = -1
yes. An opposite number is the negative of a positive number, for example -5 and +5 are opposite numbers. Since minus x plus is minus and plus x minus is minus and plus x plus is plus and minus x minus is plus then the product of opposites is the same.
If the second number is a multiple of the prime number, than the LCM is the second number. If the second number is not a multiple of the prime number, then the two numbers are relatively prime, and the LCM is the product of the two numbers.
The assertion in the question is simply not true.
90