Using the discriminant the possible values of k are -9 or 9
-0.82 , -4.82
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
Find values for the variable that satisfy the equation, that is if you replace those values for the variable into the original equation, the equation becomes a true statement.
Select a few values for "x"; calculate the corresponding "y" values; plot the points on the graphing paper; join the points with lines. In fact, that's the method used to draw just about any graph.
In the equation x2 = 6x - 9, all terms must be moved to one side of the equals sign, giving x2 - 6x + 9 = 0. This becomes factorable to (x -3)(x-3).
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
A squared plus b squared equils c squared
zeros values at which an equation equals zero are called roots,solutions, or simply zeros. an x-intercept occurs when y=o ex.) y=x squared - 4 0=(x-2)(x+2) (-infinity,-2)(-2,2) (2,infinity)
(52/11, 101/11) and (-2, -11) Rearrange 3x-y = 5 into y = 3x-5 and substitute this into the curve equation and then use the quadratic equation formula to find the values of x which leads to finding the values of y by substituting the values of x into y = 3x-5.
-0.82 , -4.82
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
The total squared error between the predicted y values and the actual y values
(x, y) = (-3, -3) or (3, 3)
It depends on the domain of y. If that is restricted to non-negative values, then the answer is yes. But if y is allowed to be negative, then the answer is no because then there are two values of y for each non-zero value of x.
Answer: (-2, 5) and (5, -9) Merge the two equations together and form a quadratic equation in terms of x. Solving the quadratic equation gives x = -2 or x = 5 Substituting the above values into the linear equation will give the coodinates. So when x = -2 then y = 5 and when x = 5 then y = -9
It is, in fact, an identity - which is an equation which is true for all values of the variable.
n = 3/2, n = 2