x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
if x2 + 7 = 37, then x2 = 29 and x = ±√29
C and D
x2+10x-33.33 = 0 Using the quadratic equation formula will give you two solutions which are: x = -12.63740794 to 8 decimal places. or: x = 2.63740794 to 8 decimal places
It has two equal solutions of 2
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
2 this Domo
x = 2 and x = -5
There are no solutions because the discriminant is less than zero
It has no solutions because the discriminant of the quadratic equation is less than zero.
None because the discriminant is less than zero
There are no real solutions because the discriminant of the quadratic equation is less than zero.
x2 + x2 = 2x2
x = 5 or x = 6
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.