x2+7x+3 = 0
Using the quadratic equation formula the solutions are:-
x = -6.541381265 or x = -0.4586187349
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4
None because without an equal it is not an equation. But if it was in the form of x2+7x+12 = 0 then it would have 2 solutions which are x = -3 and x = -4
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
Did you get the question from sevenstar academy, Algebra.
x2+7x+12
(x + 3)(x + 4)
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2 + 7x + 6 = (x + 6) (x + 1)
x=4 x=0