3(4x*-2)=6(2x-1)
2x + 7 = 1 Therefore, 2x = -6 x = -6/2 x = -3
If: 2x+y = 1 Then: y = 1-2x If: x^2 + xy + y^2 = 7 Then: x^2 +x(1-2x) +(1-2x)^2 = 7 So: x^2 +x-2x^2 +1-4x+4x^2 -7 = 0 Collecting like terms: 3x^2 -3x -6 = 0 Divide all terms by 3: x^2 -x -2 = 0 Factorizing (x+1)(x-2) = 0 => x = -1 or x = 2 Solutions by substitution: (-1, 3) and (2, -3)
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
The inequality with the terms 2x, 3 and 7 can be written as 2x -3 = 7, 2x + 3 = 7, 2x * 3 = 7, and 2x/3 = 7. This means that the solutions are 5, 2, 7/4, and 21/2 respectively.
If you mean: 2x+y = -6 and 5x-3 = 7 then the solutions are x = -1 and y = -4
2x + 3 = 4x - 7 <=> 4x - 7 = 2x + 3 <=> 2x = 10 <=> x = 5 - - - 2x + 3 = 4x - 7 Take the 2x from each side of the equation. 3 = 2x - 7 Get the numerals together 7 + 3 = 2x Therefore 10 = 2x Therefore 5 = x
2x+3 = 7 2x = 7-3 2x = 4 x = 2
2x-3 = 9 2x = 9+3 2x = 12 x = 6
2x+3<7 2x<7-3 2x<4 x<2
If 2x - 3y = 7, -3 y = 7 - 2x or y = (2x - 7)/3, or y = (2/3)x - (7/3). The slope is 2/3 and the y-intercept is -(7/3).
You did not state the operation: add or subtract. Is it 2x + 3 + 4 = 17? Is it 2x - 3 + 4 = 17?
5x+7 = 2x-3 5x-2x = -3-7 3x = -10 x = -10/3
2x 5 -7 = 3
Expanding the brackets: 6x+21 = 3(2x+7)
7 and 3 - 2x are factors of 21 - 14x