(5x - 1)(x + 3)
x2+5x+6 = (x+2)(x+3)
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
Despite my serious qualms with the wording of your question, I am assuming it to be the factoring of x2-2x+3 This is not factorable. As long as there is a positive 3 in the position of the constant element, there can only be -4 or 4 for the coefficient of the single x. Perhaps you made an error in entering the question, so I will provide some likely alternatives. If the trinomial read as x2-2x-3, then it would be factorable and would be (x-3)(x+1) If the trinomial read as x2-4x+3, then it would be factored as (x-3)(x-1) If the trinomial read as x2+4x+3, then it would be factored as (x+3)(x+1)
14x2 + 29x - 15= 14x2 + 35x - 6x - 15= 7x(2x + 5) - 3(2x + 5)= (2x + 5)(7x - 3)
(2x + 1) (x + 3) = 2x2 + 7x + 3
9x+3
(2x + 1)(x + 3) are the factors.
(x + 3)(x + 3)
(x + 10)(x + 3)
(5x - 1)(x + 3)
Yes (x+3(x+3)
Factors are (7y - 3)(7y - 2) so it's not a perfect square.
is 28x squared? if it is, the answer would be, 3(2x+5)(4x+3).
(x - 10)(x - 3)
(x - 3)(x - 11)
2x2+9x+9 = (2x+3)(x+3) when factored